- Costs of two watches were in the ratio of 16 : 23. The cost of first watch increases by 10% and that of second by Rs. 477. Now the costs of two watches are in a ratio of 11 : 20. The price of the second watch (in Rs.) in the beginning was
Correct Option: B
Given in question , The ratio of cost price of two watches = 16 : 23Let C.P. of first watch = Rs.16x
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C.P. of second watch = Rs. 23x
According to the question,
| Ratio after corresponding increases = | |
| 20 |
| ⇒ | = | ||
| 100(23x + 477) | 20 |
| ⇒ | = 1 | |
| 5(23x + 477) |
⇒ 160x = 115x + 2385
⇒ 160x – 115x = 2385
⇒ 45x = 2385
| ⇒ x = | = 53 | |
| 45 |
∴ Original C.P of second watch = Rs. 23x = Rs. (23 × 53 )
Original C.P of second watch = Rs.1219
- Costs of two watches were in the ratio of 16 : 23. The cost of first watch increases by 10% and that of second by Rs. 477. Now the costs of two watches are in a ratio of 11 : 20. The price of the second watch (in Rs.) in the beginning was
Correct Option: B
Given in question , The ratio of cost price of two watches = 16 : 23Let C.P. of first watch = Rs.16x
C.P. of second watch = Rs. 23xAccording to the question,
| Ratio after corresponding increases = | |
| 20 |
| ⇒ | = | ||
| 100(23x + 477) | 20 |
| ⇒ | = 1 | |
| 5(23x + 477) |
⇒ 160x = 115x + 2385
Rs 16x2
⇒ 160x – 115x = 2385⇒ 45x = 2385
| ⇒ x = | = 53 | |
| 45 |
∴ Original C.P of second watch = Rs. 23x = Rs. (23 × 53 )
Rs-16x Os X
Original C.P of second watch = Rs.1219